600w^2+10w-600=0

Solution for 600w^2+10w-600=0 equation:

600w^2+10w-600=0

a = 600; b = 10; c = -600;
Δ = b2-4ac
Δ = 102-4·600·(-600)
Δ = 1440100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1440100}=\sqrt{100*14401}=\sqrt{100}*\sqrt{14401}=10\sqrt{14401}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10\sqrt{14401}}{2*600}=\frac{-10-10\sqrt{14401}}{1200}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10\sqrt{14401}}{2*600}=\frac{-10+10\sqrt{14401}}{1200}
$